1x+y=10 and x-y= 5 than find the value of x
Answers
Answered by
1
Answer:
x + y = 10
x.y = 16
Working
If x.y = 16
Then y = 16/x
Substitute for y in x + y = 10
Therefore x + 16/x = 10
Multiply throughout by x
Therefore
x2 + 16 = 10x (note by writing x2 I mean x-squared)
Subtracting 10x from each side of the equation gives
x 2 - 10x + 16 = 0
Solving the quadric equation gives factors
(x - 8) (x-2) = 0
Either (x-8) = 0
Or (x-2) = 0
(because one of those factors has to be zero to give a product of zero on RHS of equation)
Solution is
x = 8 or x = 2
Answered by
1
Step-by-step explanation:
the value of x is 7.5
y is 2.5
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