Math, asked by kkuummaarraallaa, 5 months ago

1x2-2(5+2k)x+3(7+10k)=0

Answers

Answered by deevanshpal

2

Answer:

k = -13/(30-4x)

Step-by-step explanation:

2-2(5+2k)x +3(7+10k) = 0

2 -10 - 4kx + 21 +30k = 0

13 - 4kx +30k =0

or 30k -4kx = -13

k( 30 -4x) = -13

or k = -13/(30-4x)

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