1x5=5
aswer the following question :
A Social Welfare Association decides to supply drinking water for the flood
affected people. The drinking water is filled in a water tanker which is in
the shape of a cylinder with hemispherical end as shown in the figure. The
whole length of the tanker is 4-2 metre and the diameter of base of the cylinder and two hemispheres are each 1.2m .if they distribute drinking water to 60 people in a container ,each is in the shape of cylinder of radius 21 cm and height 50 cm, find the quantity of water left in the tanker after distribution in litre
Answers
Answer:
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Answer:
Quantity of water left in the tanker = 1,499 litters
Step-by-step explanation:
The quantity of water left in the tanker after distribution = Total quantity - Distributed quantity
Total quantity = Volume of the tanker
Volume of the cylinder of 4.2 m length and 1.2 m of a diameter.
Volume of cylinder = π r² L
(given L = 4.2m and diameter = 1.2m)
Substituting, we get Volume (cylinder) = 22/7 * 0.6 * 0.6 * 4.2 = 4.752 m³
Volume of 2 hemispheres at the end = 2* 2πr³/3 = 4 * 22/7 * (0.6)³ / 3 = 792 / 875 m³
Volume of tanker = 4.752 + 792/875 = 5.657 m³
Distributed quantity = 60 times the volume of a cylinder of radius 21 cm and height is 50 cm
= 60 * πr²L
= 60 * 22/6 * 21² * 50
= 4,158,000 cm³
= 4.158 m³
The quantity of water left in the tanker after distribution = 198/35 - 4.158 = 1.499 m³
1 m³= 1,000 litter
So quantity of water left in the tanker after distribution = 1.499 * 1000 = 1499 litters
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