2×0^16-8.68×10^13
please solve in step by step
Answers
Answered by
0
Answer: Step-By-Step
hv=hv0+KE
Threshold frequency (v0)=8.68×1015Hz(s−1)
Frequency of light (v)=2×1016Hz
KE =h(v−v0)
=6.626×10−34(2×1016−8.68×10−15)
KE=7.5×10−18J
Maximum kinetic energy of photoelectrons =7.5×10−18J
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Answered by
0
Answer:
- 86800000000000
Step-by-step explanation:
Firstly,
2d 0^16 = 0
secondly,
8.68 × 10^13 = 86800000000000
& thirdly,
0 - 86800000000000 = - 86800000000000
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