Question

(-2)^0*(-2)^3*(-2)^-1*(-2)^-2)^-2=x

Answer 1

Step-by-step explanation:

(-2)^0=1

(-2)^3=-8

(-2)^-1=1/-2=-1/2

((-2)^-2)^-2=(-2)^-2*-2=(-2)^4=16

then x=

= 1*(-8)*(-1/2)*16

=64

if this helps you mate

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Answer 2

Answer:

64

Step-by-step explanation:

(-2)^0 * (-2)^3 * (-2)^-1 * [(-2)^-2]^-2 = x

1 * -8 * 1/-2 * {-2} ^ (-2 * -2)               = x

-8 * 1/-2 * (-2) ^4                              =  x

4 * 16                                               = x

64                                                  = x   (answer)

hope this is helpful to u !