Question

2. 0.24g sample of a compound of oxygen and boron was found by analysis to contain
oxygen and 0.096g of boron. Calculate the percentage composition of
the compound by weight. (AS,)
0.144g of the compound by weight​

Answer 1

Answer:

Mass of the given sample compound = 0.24g

Mass of boron in the given sample compound = 0.096g

Mass of oxygen in the given sample compound = 0.144g

% composition of compound = % of boron and % of oxygen

Therefore % of boron = (mass of boron)/(mass of the sample compound) x 100

= 40%

Therefore % of oxygen = (mass of oxygen) / (mass of the sample compound) x 100

= 60%