Question

2=0
2c -35 -
22 - 3 - 15 =
$x - 3y - 2 = 0 and 3x - 3y - 15 = 0$
substitution method​

Answer 1

$\begin{gathered} {( \frac{2 + \sqrt{5} }{2 - \sqrt{5} } )}^{2} - {( \frac{2 - \sqrt{5} }{2 + \sqrt{5} } )}^{2} \\ = \frac{9}{ - 1} - ( \frac{ - 1}{9} ) \\ = - 9 + \frac{1}{9} \\ = \frac{ - 81 + 1}{9} \\ = \frac{ - 80}{9} \\ = - 8.88888889\end{gathered}$

Answer 2

Answer:

x=13/2, y=3/2

Step-by-step explanation:

x-3y-2=0__ (i) eq. and 3x-3y-15=0__ (ii)

from equation (i)

x= 2+3y__(iii)

using equation iii in ii

3(2+3y)-3y-15=0

6+9y-3y-15=0

9y-3y= 15-6

6y= 9

y=9/6

y= 3/2

using y=3/2 in iii

x=2+3y

x=2+3(3/2)

x=2+9/2

x=4+9 divide by 2

x= 13/2