Question

(2^0 -3^0)×4^0=??

a)2
b) 1
c)0
b)3​

Answer 1

Answer:

a 2

Step-by-step explanation:

unitary method se hoga

Answer 2

Answer:

(c) 0

explanation:

$➞ \: \sf { \: {(2}^{0} - {3}^{0}) \times {4}^{0} }</u></p><p><u>$

$➞\: \sf {(1 - 1) \times 1}</u></p><p><u>$

$➞\: \sf {0 \times 1}</u><u>$

$➞\: \sf \: 0</u><u>$

[any number to the power of 0 is 1,as we are multiplying the number the same time as the power is given( with 1)

i.e. 2³ = 1 × 2 × 2 × 2

here, we'd multiply 2 three times with 1

but if it's given as-

2^0 = 1 × no two's

we'd multiply 1 with zero two(s). That's how we get a^0 = 1,

where a is not equal to 0]