Question

(2)
0°
pa
The amount of heat energy required to
convert 10 g ice at 0°C to vapour at 100°C
is :
sorts
(Given : specific heat of water is
4200 J kg-1K-1, specific latent heat of
melting of ice is 336 kJ kg-1 and specific
latent heat of vapourization of water is
2260 kJ kg-1.)
(A) 336 k]
Q501 = GISS!
27065
(B) 398.95 kJ
(C) 22.6 k]
(D) 30.160 kJ​

Answer 1

Answer:

b)398.95 ki

good morning have a great day

Answer 2

Mass of ice=1g

Temp of ice=0 degree C

1 First the ice at 0 degree C is to be converted into water at 0 degree C

Heat required at this stage

= Mass of the ice x Latent heat of fusion of ice

=1x 80 =80 cal

2 Now the temperature of water is to be increased from 0 to 100 degree C

Heat required for this =Mass of water x rise in temperature x specific heat of water

=1 x100 x1= 100 cal

3 Now this water at100 degree C is to be converted into vapour

Heat required for this

=Mass of water x Latent heat

= 1 x 536 =536 cal

Total heat required

=80 +100 +536=716 cal