Chemistry, asked by narenchettri7738, 6 months ago

2 ЕО +02----- 2CO2
2х22.4L
at N+P
2x22.4 of CO required 32g oxygen
44.8L of CO required 32g oxygen
84L of CO required 32/44.8×84g
=60g​

Answers

Answered by Anonymous
0

Answer:

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