Question

2.03bar in p/q form
plz answer fastttttt​

Answer 1

Let 2.030303... be p/q _____eq.(i)

where p and q are integers and q ≠ 0.

By multiplying eq.(i) by 100, we get

203.030303... = 100p/q _____eq.(ii)

By subtracting eq.(i) from eq.(ii), we get

203.030303... - 2.030303... = (100-1)p/q

or, 201 = 99p/q

or, 201/99 = p/q

or, 67/33 = p/q

2.030303... in p/q form, where p and q are integers and q ≠ 0, is 67/33 .

Answer 2

$\huge{ \boxed{ \sf \: solution}}$

Let 2.030303... be p/q _____eq.(i)

where p and q are integers and q ≠ 0.

By multiplying eq.(i) by 100, we get

203.030303... = 100p/q _____eq.(ii)

By subtracting eq.(i) from eq.(ii), we get

203.030303... - 2.030303... = (100-1)p/q

or, 201 = 99p/q

or, 201/99 = p/q

or, 67/33 = p/q

2.030303... in p/q form, where p and q are integers and q ≠ 0, is 67/33 .