Question

2.0g of a metal oxide on strong heating 1 1 2 ml of O2 gas at STP . Equivalent weight of the metal is

Answer 1

Answer:

firstly calculate mole of oxygen in stp mole of O2= given volume in litter/ 22.4 lit then put the value,, nO2=112×10^-3/22.4 then mole of oxygen is 5×10^-3 ( note= eq mole= mole× eq value) eq mole = 5×10^-3×4 means eq mole for O2 is 20×10^-3 here we calculate eq mole because mole is different for another molecule but eq. mole is always equal for LHS and RHS of equation eq mole= weight in gm of metal oxide / eq weight then put the value , 20×10-3 = 2/ eq weight of metal oxide then after solving eq weight of metal oxide is 100 ..... eq weight of metal oxide = eq weight of metal +eq weight of oxygen then 100= eq weight of the metal+ 8 ( for oxygen) then eq weight of metal is _______ 92 and hope it may help you