(2,1)(1,x)(2,-2) are collinear find x
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B
0
Let the points A(1,2),B(1,x) and C(2,3) are collinear then area of triangle made by these points will be zero.
⇒
2
1
[x
1
(y
2
−y
3
)+x
2
(y
3
−y
1
)+x
3
(y
1
−y
2
)]
⇒
2
1
[(x−3)+(−1)(3−2)+2(2−x)]=0
⇒x−3−1+2(2−x)=0
⇒x−3−1+4−2x=0
⇒−x−4+4=0
⇒x=0
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