Question

√2-1/√2+1

rationalize the denominator

don't give wrong answer


how are you?all​

Answer 1

ANSWER :-

$\frac{\sqrt{2}-1 }{\sqrt{2} +1} =\frac{\sqrt{2}-1 }{\sqrt{2} +1} \times\frac{\sqrt{2} -1}{\sqrt{2} -1} \\\\\\=\frac{(\sqrt{2} -1)^{2} }{(\sqrt{2} )^{2}-1^{2} } \\\\=\frac{2+1-2\sqrt{2} }{2-1} \\\\= 3-2\sqrt{2}$

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