Question

2 - (+1) - 2 - (-3) =
a) 0
b) 1
c) 2
d) 3​

Answer 1

Answer:

c will be the answer. hope this will help you.

Answer 2

Answer:

Let the coordinates of

A = (X₁, Y₁)

B = (X₂, Y₂)

C = (X₃, Y₃)

D = (X₄ , Y₄)

\green{By \: distance \: formula : }Bydistanceformula:

AB \: = \sqrt{(X2 - X1) + (Y2 - Y1)}AB=(X2−X1)+(Y2−Y1)

AB = \sqrt{(3 - ( -1 ) { }^{2} + (1 - 0) {}^{2} }AB=(3−(−1)2+(1−0)2

AB= \sqrt{(3 + 1) {}^{2} + (1) {}^{2} }AB=(3+1)2+(1)2

AB \: = \sqrt{(4) {}^{2} + 1}AB=(4)2+1

AB = \sqrt{16 + 1} = \sqrt{17}AB=16+1=17

Now,

BC = \sqrt{(X3 - X2) {}^{2} + (Y3 - Y2) {}^{2} }BC=(X3−X2)2+(Y3−Y2)2

BC = \sqrt{(2 - 3) {}^{2} + (2 - 1) {}^{2} }BC=(2−3)2+(2−1)2

BC = \sqrt{( - 1) {}^{2} + (1) {}^{2} }BC=(−1)2+(1)2

BC = \sqrt{1 + 1} = \sqrt{2}BC=1+1=2

Now,

CD = \sqrt{(X4 - X3) {}^{2} + (Y4 - Y3) {}^{2} }CD=(X4−X3)2+(Y4−Y3)2

CR = \sqrt{( - 2 - 2) {}^{2} + (1 - 2) {}^{2} }CR=(−2−2)2+(1−2)2

CD = \sqrt{( - 4) { }^{2} + ( - 1) {}^{2} }CD=(−4)2+(−1)2

CD = \sqrt{16 + 1} = \sqrt{17}CD=16+1=17

Now,

AD = \sqrt{(X4 - X1) {}^{2} + (Y4 - Y1) {}^{2} }AD=(X4−X1)2+(Y4−Y1)2

AD = \sqrt{ ( - 2 - (1) {}^{2} + (1 - 0) {}^{2} }AD=(−2−(1)2+(1−0)2

AD= \sqrt{( - 2 + 1) {}^{2} + (1) {}^{2} }AD=(−2+

Hope this will help u!!!