Math, asked by sumitt64841, 1 day ago

2^1/2 * 4^1/4* 8^1/8 * 16^1/16 * 32^1/32 = k^1/32

Answers

Answered by jm03041983
1

Step-by-step explanation:

2^1/2 * 4^1/4* 8^1/8 * 16^1/16 * 32^1/32 = k^1/32

or 2^(16 +16+12+8+5)/32 = k^1/32

or 2^57/32 = k^1/32

k = 2^57

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