Question

2 1.2. In ΔΑΒC, ΑΒ = 4 cm, BC = 7 cm and AC = 3 cm. In APQR, PQ = 14 cm, RP = 8 cm and QR = 6 cm. Then: (α) ΔΑΒC - ΔΡQR. (b) ΔΑΒC - ΔQRP (c) ΔBAC - ΔΡQR (d) ΔBCA - ΔΡQR​

Answer 1

Answer:

need to think

Step-by-step explanation:

Answer 2

Given:

In ΔΑΒC, ΑΒ = 4 cm, BC = 7 cm and AC = 3 cm.

In ΔPQR, PQ = 14 cm, QR = 6 cm and RP = 8cm.

To find:

The correct option.

Solution:

Two triangles ΔΑΒC and ΔPQR are said to be similar if their corresponding sides are in the same proportion. This means

$\frac{AB}{PQ} = \frac{BC}{QR} = \frac{AC}{PR}$

Now, we will check the options and apply values of sides of triangles we have

(a) ΔΑΒC - ΔΡQR, we have

$\frac{4}{14} ≠ \frac{7}{6} ≠ \frac{3}{8}$

$\frac{2}{7} ≠ \frac{7}{6} ≠ \frac{3}{8}$

Hence, this option is wrong.

Similarly, we check the other three options.

(b) ΔΑΒC - ΔQRP

$\frac{4}{6} ≠ \frac{7}{8} ≠ \frac{3}{14}$

$\frac{2}{3} ≠ \frac{7}{8} ≠ \frac{3}{14}$

Hence, this option is wrong.

(c) ΔBAC - ΔΡQR

$\frac{4}{14} ≠ \frac{3}{6} ≠ \frac{7}{8}$

$\frac{2}{7} ≠ \frac{1}{2} ≠ \frac{7}{8}$

Hence, this option is wrong.

(d) ΔBCA - ΔΡQR

$\frac{7}{14} = \frac{3}{6} = \frac{4}{8}$

$\frac{1}{2} = \frac{1}{2} = \frac{1}{2}$

Hence, this option is correct.

Hence, the correct option is (d) ΔBCA - ΔΡQR.