Question

(2.1) 2x (1.22
find the value​

Answer 1

Answer:

x=3

Step-by-step explanation:

2^2x+2=2.2^2x-1

2x+2=2x-1

2x-2x= -2-1

x=1

Answer 2

Answer:

ANSWER

Given equation 2x

2

−2(2a+1)x+a(a+1)=0

Let f(x)=2x

2

−2(2a+1)x+a(a+1)

The condition for a to lie in between the roots is

a.f(a)<0

⇒2a

2

−2a(2a+1)+a(a+1)<0(∵A=2>0, so f(a)<0)

⇒−a

2

−a<0

⇒a

2

+a>0

⇒a>0 or a<−1.