Question

(2^-1 × 3^-1)^-1 × 4^-1

answer right or I'll report​

Answer 1

Answer:

$( {2}^{ - 1} \times {3}^{ - 1} ) ^{ - 1} \times {4}^{ - 1} \\ = ( \frac{1}{2} \times \frac{1}{3} ) ^{ - 1} \times {4}^{ - 1} \\ = ( \frac{1}{6} )^{ - 1} \times {4}^{ - 1} \\ =( {6}^{ - 1} )^{ - 1} \times {4}^{ - 1} \\ = 6 \times \frac{1}{4} \\ = \frac{6}{4} \\ = \frac{3}{2} \\ = 1.5$