Question

(2^-1 - 3^-1)^-1
plz say this ans ​

Answer 1

$Given \: ( 2^{-1} - 3^{-1} )^{-1}$

$= \Big( \frac{1}{2} - \frac{1}{3} \Big)^{-1}$

$= \Big( \frac{3-2}{6}\Big)^{-1}$

$= \Big( \frac{1}{6}\Big)^{-1}$

$= \frac{6}{1}$

$= 6$

Therefore.,

$\red{( 2^{-1} - 3^{-1} )^{-1} }\green { = 6}$

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