Question

[2^(- 1)+ 3^(- 1)+ 4^(- 1) ]^0 ​

Answer 1

Answer:

x^0 = 1 answer is 1

Step-by-step explanation:

[(2^(-1) + 3^(-1) + 4^(-1)] = x (note: without 0's power)

x ^ 0 = 1

So answer is 1

HOPE ITS CORRECT