Question

(2^-1 + 3^-1 + 5^-1)0​

Answer 1

Let's simplify step-by-step.

$( {2}^{ - 1} + {3}^{ - 1} + {5}^{ - 1} )(0)$

$( \frac{1}{2} + {3}^{ - 1} + {5}^{ - 1} )(0)$

$= ( \frac{1}{2} + \frac{1}{3} + {5}^{ - 1} )(0)$

$= (\frac{5}{6} + \frac{1}{5} )(0)$

$= \frac{31}{30} (0) \\ \\ = 0$

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