Question

(2^-1-3^-1) divided by (4^-1 + 6^-1)

Answer 1

Question:

(2^-1-3^-1) divided by (4^-1 + 6^-1)

Answer:

$= > \frac{ {2}^{ - 1} - {3}^{ - 1} }{ {4}^{ - 1} + {6}^{ - 1} }$

$= > \frac{ \frac{1}{2} + \frac{1}{3} }{ \frac{1}{4} + \frac{1}{6} }$

$= > \frac{ \frac{5}{6} }{ \frac{10}{24} }$

$= > \frac{5}{6} \times \frac{24}{10}$

$= > 2$

Hope this answer helps you ^_^ !