Question

() = ^2−1/ ^3+6^2+t Determine where the given function is discontinuous.

Answer 1

Answer:

Start by factoring the numerator and denominator of the function. A point of discontinuity occurs when a number is both a zero of the numerator and denominator. Since is a zero for both the numerator and denominator, there is a point of discontinuity there. To find the value, plug in into the final simplified equation.

Step-by-step explanation:

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