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2(+1)−3+7=5 Answer the following question (CH- linear equations with one variable)

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Answered by nirupama1502
1

2(+1)−3+7=5 Answer the following question (CH- linear equations with one variable)Page No 24:

Question 10:

Solve:

ANSWER:

14y − 8 = 13

Transposing 8 to R.H.S, we obtain

14y = 13 + 8

14y = 21

Dividing both sides by 14, we obtain

Page No 24:

Question 11:

Solve:

ANSWER:

17 + 6p = 9

Transposing 17 to R.H.S, we obtain

6p = 9 − 17

6p = −8

Dividing both sides by 6, we obtain

Page No 24:

Question 12:

Solve:

ANSWER:

Transposing 1 to R.H.S, we obtain

Multiplying both sides by 3, we obtain

Page No 28:

Question 1:

If you subtract from a number and multiply the result by, you get. What is the number?

ANSWER:

Let the number be x. According to the question,

On multiplying both sides by 2, we obtain

On transposing to R.H.S, we obtain

Therefore, the number is .

Page No 28:

Question 2:

The perimeter of a rectangular swimming pool is 154 m. Its length is 2 m more than twice its breadth. What are the length and the breadth of the pool?

ANSWER:

Let the breadth be x m. The length will be (2x + 2) m.

Perimeter of swimming pool = 2(l + b) = 154 m

2(2x + 2 + x) = 154

2(3x + 2) = 154

Dividing both sides by 2, we obtain

3x + 2 = 77

On transposing 2 to R.H.S, we obtain

3x = 77 − 2

3x = 75

On dividing both sides by 3, we obtain

x = 25

2x + 2 = 2 × 25 + 2 = 52

Hence, the breadth and length of the pool are 25 m and 52 m respectively.

Video Solution for linear equations in one variable (Page: 28 , Q.No.: 2)

NCERT Solution for Class 8 math - linear equations in one variable 28 , Question 2

Page No 28:

Question 3:

The base of an isosceles triangle is cm. The perimeter of the triangle is cm. What is the length of either of the remaining equal sides?

ANSWER:

Let the length of equal sides be x cm.

Perimeter = x cm + x cm + Base = cm

On transposing to R.H.S, we obtain

On dividing both sides by 2, we obtain

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