Math, asked by deepankshisinghalocc, 6 months ago

2^1/3 solve this equation

Answers

Answered by prdip9178
1

Answer:

Let y=2^1/3

Taking log both sides

log y = log (2^1/3)

log y= (1/3)log2 ——[log(a^b)=(b)log(a)]

log y=(1/3)0.3010 ———-[log 2=0.3010]

log y= 0.1003

Taking antilog both sides

y= 1.2598

Answered by srustimishrais
1

Step-by-step explanation:

may be this can help you if you question was about integrating

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