2^1/3 solve this equation
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Answer:
Let y=2^1/3
Taking log both sides
log y = log (2^1/3)
log y= (1/3)log2 ——[log(a^b)=(b)log(a)]
log y=(1/3)0.3010 ———-[log 2=0.3010]
log y= 0.1003
Taking antilog both sides
y= 1.2598
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Step-by-step explanation:
may be this can help you if you question was about integrating
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