Question

[(2)^-1 + (4)^-1 + (3)^-1]^-1​

Answer 1

Answer:

$\frac{12}{13}$

Step-by-step explanation:

$({2}^{ - 1} + {4}^{ - 1} + {3}^{ - 1})^{ - 1}$

$= (\frac{1}{2} + \frac{1}{4} + \frac{1}{3})^{ - 1}$

$= ( \frac{6 + 3 + 4}{12} )^{ - 1}$

$= ( \frac{13}{12} )^{ - 1}$

$= \frac{12}{13}$