Question

[(2)-¹+(4)-¹+(3)-¹]-¹​

Answer 1

Your solution:

$( {2}^{ - 1}) + ( {4}^{ - 1}) + ( {3}^{ - 1}) \: whole - 1 \\ = ( \frac{1}{2} + \frac{1}{4} + \frac{1}{3})^{ - 1} \\ = 2 + 4 + 3 = 9.$