Math, asked by mrrohitxiingh, 1 month ago

( 2^-1 - 4^-1 - 6^-1 ) ÷ ( 3/2 )^-2​

Answers

Answered by uzairriazdgk
1

Answer:

( 2^-1 - 4^-1 - 6^-1 ) ÷ ( 3/2 )^-2=(1/2-1/4-1/6)÷4/9

( 2^-1 - 4^-1 - 6^-1 ) ÷ ( 3/2 )^-2=(6-3-2)/12×9/4

( 2^-1 - 4^-1 - 6^-1 ) ÷ ( 3/2 )^-2=9/48=3/16

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