Question

(2-¹÷5-¹)²× ( -5/8)-¹​

Answer 1

Given :   (2⁻¹÷5⁻¹)²× ( -5/8)⁻¹​

To Find :  Simplify

Solution:

Laws of exponents

$\begin{align} & {{\text{a}}^{n}}\times {{a}^{-n}}=1\text{ or }{{\text{a}}^{n}}=\frac{1}{{{a}^{n}}} \\ & {{a}^{m}}\times {{a}^{n}}={{a}^{m+n}} \\ & \frac{{{a}^{m}}}{{{a}^{n}}}={{a}^{m-n}} \\ & {{\left( {{a}^{m}} \right)}^{n}}={{\left( {{a}^{n}} \right)}^{m}}={{a}^{mn}} \\ & {{a}^{m}}\times {{b}^{m}}={{\left( ab \right)}^{m}} \\ & \frac{{{a}^{n}}}{{{b}^{n}}}={{\left( \frac{a}{b} \right)}^{n}} \\ & {{a}^{0}}=1 \\ \end{align}$

(2⁻¹÷5⁻¹)²× ( -5/8)⁻¹​

=  (5/2)² × ( 8/ (-5))

= (25/4) (-8/5)

=  5 * (-2)

= - 10

(2⁻¹÷5⁻¹)²× ( -5/8)⁻¹​  =  -10

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Answer 2

Answer:

this is right ans i like it