(2–¹ ÷ 5–¹) × (-5/8)–¹
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We know that the diagonals of a rhombus bisect each other at 90⁰
Let the side of the rhombus be x cm
AO = OC = AC/2 = 24/2 = 12 cm
BO = DO = BD/2 = 10/2 = 5 cm
Using Pythagoras theorem
x
2 = 122 + 52
x
2 = 144 + 25
x
2 = 169
x= √169
x= 13 cm
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mujhe nahi pata
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