Physics, asked by bsllaishram, 9 months ago

2.1. A car is moving with a velocity of 6 m/s
and with an acceleration of -1 m/s2.
What will be the (a) distance travelled
by the car before coming to rest ?
(6) time taken for coming
to rest ?​

Answers

Answered by sunilkuna99
1

Answer:

velocity of car is 6m/s

acceleration of car is -1m/s²

means deceleration

decreasing acceleration

distance traveled by car before comes to rest and time taken are to be find

as velocity = distance /time

acceleration=velocity/time

1=6/t

here minus indicates state of acceleration so need not consider it

time = 6sec

Explanation:

now distances =velocity ×time

distance=36mts

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