2.1. A car is moving with a velocity of 6 m/s
and with an acceleration of -1 m/s2.
What will be the (a) distance travelled
by the car before coming to rest ?
(6) time taken for coming
to rest ?
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Answer:
velocity of car is 6m/s
acceleration of car is -1m/s²
means deceleration
decreasing acceleration
distance traveled by car before comes to rest and time taken are to be find
as velocity = distance /time
acceleration=velocity/time
1=6/t
here minus indicates state of acceleration so need not consider it
time = 6sec
Explanation:
now distances =velocity ×time
distance=36mts
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