Question

2.
(1+cot²θ)sin²θ=1
plz answer
first on to answer WILL be marked as brainesst

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Answer 1

Answer:

(1+COT2A)sin2A=1

Step-by-step explanation:

lhs

cosec2A×sin2A (1+cot2A=cosec2A )

(cosecA × sinA=1)

1

lhs = rhs prove that

follow and thanks

Answer 2

Answer:

$\rm (1+cot^2 \theta)sin^2 \theta = 1$

$\rm \dashrightarrow 1+cot^2 \theta = \dfrac{1}{sin^2\theta}$

$\rm \dashrightarrow 1+cot^2 \theta = cosec^2 \theta \qquad ...\Bigg [ \because \ \ sin \ \theta = \dfrac{1}{cosec \ \theta} \Bigg ]$

$\rm \dashrightarrow cosec^2 \ \theta= cosec^2 \theta \qquad ...\Bigg [ \because \ \ From \ the \ identity \ : \ cosec^2 \theta - cot^2 \theta = 1 \Bigg ]$

LHS = RHS

Hence, Proved.