Question

2
1. Find the final temperature of a copper rod
Whose area of cross section changes from
10 m² to 11 m’ due to heating. The copper
rod is initially kept at 90 K. (Coefficient of
superficial expansion is 0.0021 /K)​

Answer 1

Explanation:

use formula, A=A_0(1+\beta\Delta T)A=A0(1+βΔT)

where A is area of material rod at final temperature, A_0A0 is area of material rod at initial temperature, β is coefficient of superficial expansion and ∆T is change in temperature.i.e., (T-T_0)(T−T0)

given, A_0A0 = 10 m² , A = 10m² , β = 0.0021/K and T_0=90KT0=90K

so, 11 = 10[1 + (T - 90) × 0.0021]

⇒11 = 10 + 10 × (T - 90) × 0.0021

⇒11 - 10 = (T - 90) × 0.021

⇒1/0.021 = T - 90

⇒47.62 = T - 90