2.
1) find the value of 4 if the distance between
points AC2,-2) and B (-1, 4) is 5
AB2= [(-1)-2] + [y-(-2)] 2
52 = (-3)2 +__2
25 = ____
16 = (y+2)
Y+2= ____
y+2 = 14
y= 4-2 or y= 4-2
y=__ or y=__
Value of y is ___
Answers
Answered by
66
Appropriate Question :- Find the value of k if distance between points A (2,-2) and B (-1, k) is 5.
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Given :- The distance between points A(2,-2) and B(-1, k) is 5.
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To find :- The value of k?
Solution :-
The given points are A(2, - 2) and B(-1, y).
Here,
- x₁, = 2
- y₁ = -2
- x₂ = -1
- y₂ = k.
We know that,
- AB = √{(x₂ - x₁)² + (y₂ - y₁)²}.
Putting all values in formula, we get:
→ 5 = √{(-1 - 2)² + (k - (-2))²}
→ (5)² = (-3)² + (k - (-2))²
→ 25 = (-3)² + (k + 2)²
→ 25 = 9 + (k + 2)²
→ 25 - (k + 2)² = 9
→ -(k + 2)² = 9 - 25
→ -(k + 2)² = -16
→ (k + 2)² = 16
→ k + 2 = √16
→ k + 2 = 4
→ k = 4 - 2
→ k = 2 (Ans.)
Hence, the required value of k is 2.
Answered by
123
Answer:
Correct Question :-
- Find the value of k if the distance between two points is A(2 , - 2) and B(- 1 , k) is 5.
Given :-
- Distance between two points A(2 , - 2) and B(- 1 , k) is 5.
To Find :-
- What is the value of k.
Formula Used :-
Distance Formula :
Solution :-
A(2 , - 2)
B(- 1 , k)
Let,
- x₂ = - 1
- x₁ = 2
- y₂ = k
- y₁ = - 2
According to the question by using the formula we get,
The value of k is 2 .
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