Question

2
1, If tan A + cot A = 5
find the value of tan square A + cot square A.​

Answer 1

Answer:

squaring both sides

tan^2A +cot^2A + 2 tanA cotA =25

tan^2A +cot^2A +2×tanA×1tanA=25

tan^2+ cot^2=25-2=23

Answer 2

Answer:

23

Step-by-step explanation:

tan A + cot A = 5

On squaring both sides..

${(tan \: a + cot \: a )}^{2} = {5}^{2}$

${tan}^{2} a + {cot}^{2} a + 2 \times tan \: a \times cot \: a = 25$

As tan a × cot a =1

because cot a = 1/tan a

${tan}^{2} a + {cot}^{2} a + 2 = 25$

${tan}^{2} a + {cot}^{2} a = 25 - 2 = 23$

ANS :- 23