Question

2.
(1 Point)
If tan 0 = 13, then sec 0 is equal to
(a)
1310
2
(b)
al
(c) 2
(d)
- ادب​

Answer 1

Answer:

This can be solved easily once we visualise it.

Explanation:

A)wkt, tanx = perpendicular(p)/base(b) .....(1)

B)We are given tanx=5/12 .....(2)

C)On comparing the quantities we get that p=5 and b=12

D)We require the value of hypotenuse(h),

for this we apply the Pythagoras theorum i.e,  

h

2

=

p

2

+

b

2

⇒

 

h

2

=

5

2

+

12

2

⇒

h

2

=25+144

⇒

h

2

=169

⇒

h=

√

169

⇒

h=13

..............................................................................................................

Hence , sinx = perpendicular/hypotenuse=p/h = 5/13

cosx = base/hypotenuse=b/h = **12/13* .... *(Answer)