2(1-sin^3x)÷
cos2^2x
lim
x=π÷2
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>>Applied Mathematics
>>Limits and Continuity
>>Properties of limits
>>The value of limit x→pi/21 - sin^3x/cos
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The value of
x→π/2
lim
cos
2
x
1−sin
3
x
is
Easy
Solution
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Correct option is B)
x→π/2
lim
cos
2
x
1−sin
3
x
=
x→π/2
lim
1−sin
2
x
(1−sinx)(1+sinx+sin
2
x)
=
x→π/2
lim
(1−sinx)(1+sinx)
(1−sinx)(1+sinx+sin
2
x)
=
x→π/2
lim
1+sinx
1+sinx+sin
2
x
=
1+1
1+1+1
=
2
3
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