2 + 1/tan^2A + 1 /cot²A = sec^2A + cosec^2
Answers
Answered by
0
Explanation:
LHS=tan
2
A+cot
2
A
=
cos
2
A
sin
2
A
+
sin
2
A
cos
2
A
=
sin
2
Acos
2
A
sin
4
A+cos
4
A
=
sin
2
Acos
2
A
(sin
2
A+cos
2
A)
2
−2sin
2
Acos
2
A
=
sin
2
Acos
2
A
1−2sin
2
Acos
2
A
=
cos
2
A
1
.
sin
2
A
1
−2
=sec
2
A.cosec
2
A−2
=RHS
Hence proved
Similar questions
Accountancy,
17 days ago
English,
17 days ago
Hindi,
17 days ago
Chemistry,
1 month ago
Math,
1 month ago
Social Sciences,
9 months ago
Math,
9 months ago
Physics,
9 months ago