Question

2
1 - tan A
2
1 + tan- A
1 + cot²A
(17.00
tan?
cot A
plzzzzzz solve it fast......​

Answer 1

Here, we will use, tan2A=2tanA1−tan2A

1+tanAtan(A2)=1+⎛⎝⎜2tan(A2)1−tan2(A2)⋅tan(A2)⎞⎠⎟

=1−tan2(A2)+2tan2(A2)1−tan2(A2)

=1+tan2(A2)1−tan2(A2)

=sec2(A2)cos2(A2)−sin2(A2)cos2(a2)

=sec2(A2)sec2(A2)cosA=secA

Now, tanAcot(A2)−1=⎛⎝⎜2tan(A2)1−tan2(A2)⎞⎠⎟(1tan(a2))−1

2−1+tan2(A2)1−tan2(A2)

=1+tan2(A2)1−tan2(A2)

=sec2(A2)cos2(A2)−sin2(A2)cos2(a2)

=sec2(A2)sec2(A2)cosA=secA

Answer 2

Answer:

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