Question

х
2 = 1
yi
. If sec A + tan A = p, show that :
2
p²
1
I sin A =
2
p + 1
If tan A = n tan B and sin A = m sin
that :​

Answer 1

$\bold{ \huge{ \mathfrak{Hello!}}}$

$(sin \theta + cos \theta + 1)(sin \theta - cos \theta + 1) \sec\theta \: cosec \theta$

$\longrightarrow [ {(sin \theta + cos \theta)}^{2} - {(1)}^{2} ]sec \theta \: cosec \theta$

$\longrightarrow[ {sin}^{2} \theta + {cos}^{2} \theta + 2sin \theta \: cos \theta - 1] sec \theta cosec \theta$

$\longrightarrow[ \cancel 1 + 2sin \theta \: cos \theta - \cancel1] sec \theta cosec \theta$

$\longrightarrow2 \sin \theta \: cos \theta \times sec \theta cosec \theta$

$\longrightarrow2$