Chemistry, asked by 92550, 6 months ago

2×10^30 photon of light beam emits 6.6 ×10^11 J energy , find frequency of light ​

Answers

Answered by PSN03
3

Yo

we know that

E=nhf

E=6.6*10^11

n=2*10^30

h=6.636*10^(-34)

f=E/nh

=6.6*10^11/2*10^30*6.636*10^(-34)

=0.45*10^15 Hz

Hope this helps

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