2^10+n × 4^3n-5 ÷ 2^4n+1 × 2^3n-1
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Answer to your problem is 1.
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Answered by
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=2^10+n × (2²)^3n-5 / 2^4n+1 × 2^3n-1
[use formula a^m × a^n = a^m+n ]
=2^10+n × 2^6n-10 / 2^4n+1+3n-1
=2^10+n+6n-10 / 2^7n
=2^7n / 2^7n
[use formula a^m/a^n = a^m-n ]
=2^7n-7n
=2^0
=1
[use formula a^m × a^n = a^m+n ]
=2^10+n × 2^6n-10 / 2^4n+1+3n-1
=2^10+n+6n-10 / 2^7n
=2^7n / 2^7n
[use formula a^m/a^n = a^m-n ]
=2^7n-7n
=2^0
=1
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