2,( ),( ),108. if these numbers are in AP find the empty boxes
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let first number be a
a4=108
a+3d=108
3d=106
d=106/3
now a2= a +d
a2=2+106/3
=112/3
a3=a+2d
=2+2*106/3
2+212/3
218/3
a4=108
a+3d=108
3d=106
d=106/3
now a2= a +d
a2=2+106/3
=112/3
a3=a+2d
=2+2*106/3
2+212/3
218/3
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