Math, asked by kavitamishra631, 10 months ago

2^11÷2^5=2^-5×2^2n-1, find n​

Answers

Answered by jpg810
0

Answer:

 {2}^{11} \div  {2}^{5}  =  {2}^{ - 5}  \times  {2}^{2n - 1}

 {2}^{11 - 5}  =  {2}^{ - 5 + 2n - 1}

 {2}^{6}  =  {2}^{2n - 6}

2 \: cancelled

2n - 6 = 6

2n = 12

n = 6

Hope it helps...

Mark as branliest please...

Answered by bishnupriyarout6409
0

Answer:

6

Step-by-step explanation:

According to the question,

2^11/2^5=2^-5×2^(2n-1)

=>2^6=(1/2^5)×2^(2n-1)

=>2^6×2^5=2^(2n-1)

=>2^(2n-1)=2^11

As bases are equal, they are omitted

=>2n-1=11

=>2n=11+1

=>2n=12

=>n=12/2

=>n=6

So, the value of n is 6.

THANK YOU

Similar questions