Question

бу²- 11у - 2 factorise please help me​

Answer 1

Step-by-step explanation:

6y² - 12y + y -2

6y ( y -2) + 1 ( y-2)

(6y+1)(y-2)

is your answer

Answer 2

Question

$=> 6y²-11y-2$

$=> 6y²-12y+1y-2$

$=> 6y(y-2)+1(y-2)$

$(6y+1)(y-2)$

If we factorise the 6x²-11y-2 we get (6y+1)(y-2).

_______________________

Extra

factors of y are :-

$= > 6y + 1 = 0 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: y = \frac{ - 1}{6}$

$= > y - 2 = 0 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: y = 2$

Factors of y are -1/6 & 2.

I hope it will help you please give thanks