Math, asked by Sly01, 8 hours ago

2/√11-√6 rationalise the denominator​

Answers

Answered by vishwachaitanya
2

Answer:

2(√11+√6)/5

Step-by-step explanation:

2/√11-√6 * √11+√6/√11+√6

2(√11+√6)/11-6

Answered by piughorui48
0

Answer:

Answer:

1

60

(

6

5

+

5

6

+

330

)

60

1

(6

5

+5

6

+

330

)

Step-by-step explanation:

Here, the given expression is,

1

6

+

5

11

6

+

5

11

1

For rationalizing the denominator, multiply both numerator and denominator by √6 + √5 + √11,

=

1

6

+

5

11

×

6

+

5

+

11

6

+

5

+

11

=

6

+

5

11

1

×

6

+

5

+

11

6

+

5

+

11

=

6

+

5

+

11

(

6

+

5

)

2

(

11

)

2

=

(

6

+

5

)

2

−(

11

)

2

6

+

5

+

11

=

6

+

5

+

11

6

+

5

+

2

×

6

×

5

11

=

6+5+2×

6

×

5

−11

6

+

5

+

11

=

6

+

5

+

11

2

30

=

2

30

6

+

5

+

11

Again for rationalizing the denominator, multiply both numerator and denominator by √30,

=

180

+

150

+

330

60

=

60

180

+

150

+

330

=

6

5

+

5

6

+

330

60

=

60

6

5

+5

6

+

330

=

1

60

(

6

5

+

5

6

+

330

)

=

60

1

(6

5

+5

6

+

330

)

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