Question

2.11. In a biprism experiment, red light of wavelength 6500 Å was used. It was then replaced by green light
of wavelength 5200 Å. Find the value of n for which (n + 1)th green bright band would coincide with
the nth bright band, for the same setting,​

Answer 1

Answer:

the seting is

Explanation:

red

orange

yellow

green

blue

inlue

vertian

Answer 2

Answer:

Formula,

β=

D

λd

given that n fringes of red coinciding with n+1 green fringes. Then,

nβ

r

=(n+1)β

g

n×

D

6500d

=(n+1)

D

5200d

n×65=(n+1)×52

n=

52

65−52

∴n=4

Explanation:

I HOPE THIS IS HELPFUL TO YOU

yadi apko yeh answer thik lagta he to thanks option ko jarur on karna

aur jo jo free fire lover hen follow kar dena

and

bhai/bahan apko yadi ye answer thik lagta he to mark me brillieanst kar dena

thanks