Question

2.12. A wire of length 1 m and mass 2g is in unison with a tuning
Tork of frequency 300 Hz. Calculate the tension produceu
wire.​

Answer 1

Please refer to the attachment for the solution......

Hope u get that right.....

Answer 2

The tension produced in the wire is 720 N.

Explanation:

Given that,

Length of the wire, l = 1 m

Mass, m = 2 g = 0.02 kg

Frequency of the tuning fork, f = 300 Hz

The formula of the frequency of the tuning fork is given by the formula:

$f=\dfrac{1}{2l}\sqrt{\dfrac{T}{\mu}}$

Here, $\mu$ is the mass per unit length

$\mu=\dfrac{m}{l}=\dfrac{0.002}{1}=0.002\ kg/m$

$300=\dfrac{1}{2\times 1}\sqrt{\dfrac{T}{0.002}}$

On solving we get :

T = 720 N

So, the tension produced in the wire is 720 N. Hence, this is the required solution.

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Frequency of tuning fork

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