Question

2.12g of anhydrous Na2co3 present in how much volume of solution will have 0.2 M concentration ​

Answer 1

Answer:

Concept:

The molar mass of a chemical compound is defined as the mass of a sample of that compound divided by the amount of substance in that sample, measured in moles.

Explanation:

$Molar \ mass \ of \ \mathrm{Na}_{2} \mathrm{CO}_{3}=106 \mathrm{~g} / \mathrm{mol} \begin{aligned}\text { Molarity } &=\frac{\omega t \times 1000}{M_{\omega} \times V d \cdot(\mathrm{ml})} \\0.2 &=\frac{2.12 \times 1000}{106 \times V 01 \cdot(\mathrm{ml})} \\\therefore \text { Vol. (ml) } &=\frac{2.12 \times 1000}{0.2 \times 106} \\&=100 \mathrm{ml}\end{aligned}$

The answer is 100 ml

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Answer 2

Answer:

The correct answer of this question is $100ml$

Explanation:

Given - 2.12g of anhydrous Na2co3 .

To Find - Write how much volume of solution will have 0.2 M concentration.

Now,

For a variety of reasons, anhydrous ammonia is frequently used as a nitrogen source. It contains 82 percent nitrogen, making it more concentrated than conventional nitrogen sources. Because it is used in the production of other nitrogen fertilisers, it is readily available.

2.12g of anhydrous $Na_{2}co_{3}$

Molar mass of $Na_{2}co_{3}$ is $106 g/mol$

Molarity is - $\frac{ wt . 1000 }{Mw . ol(mol)}$

$0.2 =$ $\frac{2.12 . 1000}{106 .vol(ml)}$

$vol(ml) = \frac{2.12 . 1000}{0.2 . 106}$

= $100ml$

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